solve [√5-2/√2+2][√5+2/√5-2]?
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Answer:
√5-√2+2-√10/2
Step-by-step explanation:
first rationalise the denoominator,
[(√5-√2)(√2-2)/-2][(√5+2)²/1]
(9+4√5)(2√5+2√2-4-√10)/2
Expanding and simplifying ,we get:
√5-2√2+2-√10/2
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