Question

Solve 5 and 6 in copy fast

Answer 1

(5)

Given equation is a^3 - b^3 + 1 + 3ab

It can be written as:

= > a^3 + (-b)^3 + 1^3 - 3 * a * (-b) * 1

We know that x^3 + y^3 + z^3 - 3xyz = (x + y + z)(x^2 + y^2 + z^2 - xy - yx - xz).

So,

The above equation can be written as:

= > (a - b + 1)(a^2 + b^2 + 1 + ab + b - a)

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(6)

We know that two angles are supplementary, when they add up to 180.

Let one angle = x.

Then the other angle will be 180 - x.

Given that Supplementary of an angle is one-third of its supplement.

= > x = (1/3) * (180 - x)

= > 3x = 180 - x

= > 4x = 180

= > x = 45.

So, the supplementary angle is 180 - 45 = 135.

Therefore, the angle are 45 and 135.

Hope this helps!