solve 5/x-1+1/y-2=1 and 6/x-1-3/y-2=2 using reduction methord
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the answer of this question is
x=4. y=5
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/x-1+1/y-2=2 ---) 1
6/x-1-3/y-2=1 ---) 2
let assume, 1/x-1=u, 1/y-2=v
multiply equation 1 by 3, we will get
15* u = 3* v = 6 ---) 3
add equation 2 and 3
21* u = 7
u = (1/3)
x - 1=3
x = 4
b=1/3
y – 2 = 3
y = 5
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