Math, asked by shreya250907, 1 month ago

solve 5x-7/3x=2 and check​

Answers

Answered by antrakurrey
1

Solve

1.Multiply the numbers

2.Combine multiplied terms into a single fraction

5−73=2

5x-\frac{7}{3}x=2

5x−37x=2

5+-73=2

5x+\frac{-7x}{3}=2

5x+3−7x=2

3.Find common denominator

5+−73=2

5x+\frac{-7x}{3}=2

5x+3−7x=2

3/53+−73=2

\frac{3 \cdot 5x}{3}+\frac{-7x}{3}=2

33⋅5x+3−7x=2

4.Combine fractions with common denominator

3/53+−73=2

\frac{3 \cdot 5x}{3}+\frac{-7x}{3}=2

33⋅5x+3−7x=2

3/5−73=2

\frac{3 \cdot 5x-7x}{3}=2

33⋅5x−7x=2

5 .Multiply the numbers

3/5−73=2

\frac{{\color{#c92786}{3}} \cdot {\color{#c92786}{5}}x-7x}{3}=2

33⋅5x−7x=2

1/5−73=2

\frac{{\color{#c92786}{15}}x-7x}{3}=2

315x−7x=2/6

6.Combine like terms

1/5−73=2

\frac{{\color{#c92786}{15x}}{\color{#c92786}{-7x}}}{3}=2

315x−7x=2

83=2

\frac{{\color{#c92786}{8x}}}{3}=2

38x=2/7

7.Multiply all terms by the same value to eliminate fraction denominators

83=2

\frac{8x}{3}=2

38x=2

3/83=3/2

3 \cdot \frac{8x}{3}=3 \cdot 2

3⋅38x=3⋅2

8.Cancel multiplied terms that are in the denominator

3/8

3=× 3/2

3 \cdot \frac{8x}{3}=3 \cdot 2

3⋅38x=3⋅2

8=3⋅/2

8x=3 \cdot 2

8x=3⋅2

9.Multiply the numbers

8=3/⋅2.

8x={\color{#c92786}{3}} \cdot {\color{#c92786}{2}}

8x=3⋅2

8=6

8x={\color{#c92786}{6}}

8x=6

10. Divide both sides of the equation by the same term

8=6

8x=6

8x=6

88=6

Sovle... (8=3/4)

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