Question

solve:5x²-6x-2=0 by completing the square method​

Answer 1

Answer:

$5 {x}^{2} - 6x - 2 = 0 \\ \\ dividing \: both \: sides \: by \: 5 \\ \\ {x}^{2} - \frac{6x}{5} - \frac{2}{5} = 0 \\ \\ {x }^{2} - \frac{6x}{5} = \frac{2}{5} \\ \\ third \: term = {( \frac{1}{2} \times coefficient \: of \: x) }^{2} \\ = ( \frac{1}{2} \times \frac{ - 6}{5} ) ^{2} \\ = {( \frac{3}{10}) }^{2} \\ adding \: on \: both \: sides \\ {x}^{2} - \frac{6x}{5} + {( \frac{3}{5}) }^{2} = \frac{2}{5} + {( \frac{3}{5} )}^{2} \\ ({x - \frac{3}{5}) }^{2} = \frac{2}{5} + \frac{9}{25} \\ x - \frac{3}{5} = \frac{ + }{} \sqrt{ \frac{19}{25} } \\ x = \frac{ \frac{ + }{} \sqrt{19} + 3 }{5}$

this is your answer by complete square method hope it helps to you☺️