Math, asked by naro1sjanaanee, 1 year ago

solve 6a-3b=3 3a-2b=0 fast pls....

Answers

Answered by Anurag19
0
6a - 3b = 3 ...........(i)
3a - 2b = 0 ...........(ii)
Multipling eq. (ii) by 2, we get
6a - 4b = 0 ...........(iii)
On subtracting, eq (i) and (ii), we get
b = 3
Now, putting b = 3 in eq(ii)
3a - 2(3) = 0
3a - 6 = 0
3a = 6
a = 6/3 = 2
Therefore, the values of
    a = 2 and b = 3
I hope this will help you...........
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Answered by Anonymous
1
6x-3y=3 3x-2y=0 (6-2x3)x+(-3-2x-2)y=3 3x-2y=0 (6-6)x+(-3-2><-2)y=3 3x-2y=0 0x+(-3-2><-2)y=3 3x-2y=0 o+(-3-2x-2)y=3 3x-2y=0 (-3-2x-2)y=3 3x-2y=0 (-3+4)y 3x-2y (-3+4)y 3x-2y y=3 3x-2y y=3 3x-ZX3 y=3 3x-6 y=3 3x Y=3 x=6/3 { y=3 x=2
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