Solve 6th Question plx
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the answer is 1/9
use the theorem of areas of similar triangles
HOPE IT HELPS
triABC similar triPQR...(GIVEN)
therefore by theorem of area of similar triangles
A(triABC)/A(triPQR)=AB*2/PQ*2
=1*2/3*2
=1/9
use the theorem of areas of similar triangles
HOPE IT HELPS
triABC similar triPQR...(GIVEN)
therefore by theorem of area of similar triangles
A(triABC)/A(triPQR)=AB*2/PQ*2
=1*2/3*2
=1/9
Anonymous:
Can u do the whole sum
*2 means square
Answered by
2
hlo friend
HERE IS UR ANSWER
WE KNOW THAT
ratio of area of 2 similar triangle is equal to ratio of square of their proportionate side
ar ABC/arPQR = (AB/PQ)^2
= (I/3)^2
= 1/9
I HOPE IT HELPS YOU
PLZ MARK IT AS A BRAINLIEST
HERE IS UR ANSWER
WE KNOW THAT
ratio of area of 2 similar triangle is equal to ratio of square of their proportionate side
ar ABC/arPQR = (AB/PQ)^2
= (I/3)^2
= 1/9
I HOPE IT HELPS YOU
PLZ MARK IT AS A BRAINLIEST
Thank you
wc
np bro
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