solve
6x^2-x-2=0
by completing the square
Answers
Answered by
1
Answer:
Step-by-step explanation:
x
2
+
6
x
+
2
=
0
(
x
2
+
6
x
ssssssss
)
+
2
=
0
1
2
⋅
6
=
3
. and
3
2
=
9
so we need to add
9
to get a complete square:
(
x
2
+
6
x
+
9
−
9
)
+
2
=
0
(
x
2
+
6
x
+
9
)
−
9
+
2
=
0
(
x
+
3
)
2
−
7
=
0
(
x
+
3
)
2
=
7
x
+
3
=
±
√
7
x
=
−
3
±
√
7
The solutions are:
−
3
−
√
7
,
−
3
+
√
7
Answered by
1
Step-by-step explanation:
6x²-x-2 = 0
6x²+3x-4x-2 = 0
3x(2x+1)-2(2x+1)
(3x-2) (2x+1)
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