Question

solve 7(2t-3)-2(3t-2)

Answer 1

Given(3t−2)/4−(2t+3)/3=2/3−t

Now by taking L.C.M for 4 and 3 is 12

(3(3t−2)−4(2t+3))/12=2/3−t

By transposing the above equation we can write as

(9t−6−8t−12)/12=2/3−t

t+12t=8+18

Again by transposing

t = 26/13

t = 2

Answer 2

Answer:

7(2t-3)-2(3t-2)

14t-21-6t+4

14t-6t-21+4

8t-17