Question

solve 7,9 and 10th questions.... plz

Answer 1

Co-ordinates of x(3,1/3)

Here is the 7th ans..... Hope it helps u!!

Answer 2

1.... 4√3 x² +5x -2√3 =0
⇒4√3 x² +8x -3x -2√3=0
⇒4x(√3 x+2) -√3(√3x +2) =0
⇒(√3x +2)(4x -√3) =0
⇒(√3x +2) =0 or (4x-√3) =0
⇒x = -2/√3 or √3/4
2.....x=3,y=a
2x-3y-5=0
2(3)-3(a)-5=0
6-3a=5
6-5=3a
3a=1
a=1/3
3....
ΔABE is a right triangle, right angled at B

AB²+BE² = AE²……………..(1)

(by the Pythagoras theorem)


ΔDBC is a right triangle, right angled at B

DB²+BC² = CD²…………….(2)
(by the Pythagoras theorem


Adding eq 1 & 2


AE²+CD²= (AB²+BE²)+(BD²+BC²)


AE²+CD²= (AB²+BC²)+(BE²+BD²)......(3)

[Rearranging the terms]


ΔABC is a right triangle,

AB²+BC² = AC²…………….(4)
(by the Pythagoras theorem)



Δ DBE is a right triangle

DB²+BE² = DE²………………(5)

(by the Pythagoras theorem)



AE²+CD²= (AB²+BC²)+(BE²+BD²)


AE²+CD²= AC²+DE² 

[ From equation 4 and 5]