Solve 7powerx =9power x-2
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7 ^ x = 9 ^( x - 2)
taking log both sides,
x log 7 = ( x-2 ) log 9
x log 7 = x log 9 - 2 log 9
2 log 9 = x log 9 -x log 7
2 log 3² = x [ log 9 - log 7 ]
6 log 3 = x [ log 9 / 7 ] {∵ log a-log b = log a/ b }
x= 6 log 3 / log (9/7)
taking log both sides,
x log 7 = ( x-2 ) log 9
x log 7 = x log 9 - 2 log 9
2 log 9 = x log 9 -x log 7
2 log 3² = x [ log 9 - log 7 ]
6 log 3 = x [ log 9 / 7 ] {∵ log a-log b = log a/ b }
x= 6 log 3 / log (9/7)
GauravGumber:
hey mark answer as brainliest
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