Solve: 7x + 4y = –5 and –2x + 5y = 26 by elimination method
Answers
Answered by
0
Answer: x=-3 and y=4
Step-by-step explanation: multiply eq 1 by 2 and eq 2 by 7 then you'll get 14x+8y=-10 and -14x+35y=182 name it eq 3 & 4 respectively add eq 3 and 4 14 will be eliminated and you'll get 43y=172 after that y=172÷43 then you'll get y=4 then substitute y=4 in eq 1 i.e 7x+4(4)=-5 which will become 7x=-5-16 which will become x=-23÷7 then you'll get x=-3
Answered by
1
THANKS FOR THE QUESTION !
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
GIVEN :
=> 7X + 4Y = -5 ....................1
=> -2X + 5Y = 26 .................2
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
MULTIPLY 1ST EQN BY 5 ......
=> 35X + 20Y = -25 ....................3
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
TAKE 2ND EQN AND MAKE IT READY FOR SUBSTITUTION ......
=> -2X + 5Y = 26
=> 5Y = 26 + 2X ................4
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
PUT EQN 4 IN EQN 3
=> 35X + 4 ( 5Y ) = -25
=> 35X + 4 ( 26 + 2X ) = -25
=> 35X + 104 + 8X = -25
=> 43X = -25 - 104
=> 43X = - 129
=> X = -129 / 43
=> X = -3
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
PUT X = -3 IN EQN 1
=> 7 ( -3 ) + 4Y = -5
=> -21 + 4Y = -5
=> 4Y = -5 + 21
=> 4Y = 16
=> Y = 16/4
=> Y = 4
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
HOPE IT WILL HELP U ......
THANKS AGAIN .....
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
GIVEN :
=> 7X + 4Y = -5 ....................1
=> -2X + 5Y = 26 .................2
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
MULTIPLY 1ST EQN BY 5 ......
=> 35X + 20Y = -25 ....................3
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
TAKE 2ND EQN AND MAKE IT READY FOR SUBSTITUTION ......
=> -2X + 5Y = 26
=> 5Y = 26 + 2X ................4
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
PUT EQN 4 IN EQN 3
=> 35X + 4 ( 5Y ) = -25
=> 35X + 4 ( 26 + 2X ) = -25
=> 35X + 104 + 8X = -25
=> 43X = -25 - 104
=> 43X = - 129
=> X = -129 / 43
=> X = -3
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
PUT X = -3 IN EQN 1
=> 7 ( -3 ) + 4Y = -5
=> -21 + 4Y = -5
=> 4Y = -5 + 21
=> 4Y = 16
=> Y = 16/4
=> Y = 4
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
HOPE IT WILL HELP U ......
THANKS AGAIN .....
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
chaitu251798:
good
Similar questions
Chemistry,
7 months ago
Hindi,
7 months ago
Math,
1 year ago
Social Sciences,
1 year ago
Physics,
1 year ago