Question

solve
7x+6y=3800.
3x+5y=1750. by substitution method​

Answer 1

SOLUTION:-

Given:

⚫7x +6y= 3800...........(1)

⚫3x +5y= 1750...........(2)

Substitution Method:

From equation (1), we get;

$= > 7x = 3800 - 6y \\ \\ = > x = \frac{3800 - 6y}{7} ................(3)$

Putting the value of x in equation (2), we get;

$= > 3( \frac{3800 - 6y}{7} ) + 5y = 1750 \\ \\ = > 11400 - 18y + 35y = 12250 \\ \\ = > 11400 + 17y = 12250 \\ \\ = > 17y = 12250 - 11400 \\ \\ = > 17y = 850 \\ \\ = > y = \frac{850}{17} \\ \\ = > y = 50$

And,

Putting the value of y in equation (3), we get;

$= > x = \frac{3800 -6(50) }{7} \\ \\ = > x = \frac{3800 - 300}{7} \\ \\ = > x = \frac{3500}{7} \\ \\ = > x = 500$

Thus,

The value of x = 500.

The value of y= 50

Hope it helps ☺️

Answer 2

x value is 500 and y value is 50