Solve (7y+1)/4 +1=(7y-3) /6
Answers
Answered by
1
Let's solve your equation step-by-step.
7
y
+
1
4
+
1
=
7
y
−
3
6
Step 1: Simplify both sides of the equation.
7
y
+
1
4
+
1
=
7
y
−
3
6
7
4
y
+
1
4
+
1
=
7
6
y
+
−
1
2
(Distribute)
(
7
4
y
)
+
(
1
4
+
1
)
=
7
6
y
+
−
1
2
(Combine Like Terms)
7
4
y
+
5
4
=
7
6
y
+
−
1
2
7
4
y
+
5
4
=
7
6
y
+
−
1
2
Step 2: Subtract 7/6y from both sides.
7
4
y
+
5
4
−
7
6
y
=
7
6
y
+
−
1
2
−
7
6
y
7
12
y
+
5
4
=
−
1
2
Step 3: Subtract 5/4 from both sides.
7
12
y
+
5
4
−
5
4
=
−
1
2
−
5
4
7
12
y
=
−
7
4
Step 4: Multiply both sides by 12/7.
(
12
7
)
*
(
7
12
y
)
=
(
12
7
)
*
(
−
7
4
)
y
=
−
3
7
y
+
1
4
+
1
=
7
y
−
3
6
Step 1: Simplify both sides of the equation.
7
y
+
1
4
+
1
=
7
y
−
3
6
7
4
y
+
1
4
+
1
=
7
6
y
+
−
1
2
(Distribute)
(
7
4
y
)
+
(
1
4
+
1
)
=
7
6
y
+
−
1
2
(Combine Like Terms)
7
4
y
+
5
4
=
7
6
y
+
−
1
2
7
4
y
+
5
4
=
7
6
y
+
−
1
2
Step 2: Subtract 7/6y from both sides.
7
4
y
+
5
4
−
7
6
y
=
7
6
y
+
−
1
2
−
7
6
y
7
12
y
+
5
4
=
−
1
2
Step 3: Subtract 5/4 from both sides.
7
12
y
+
5
4
−
5
4
=
−
1
2
−
5
4
7
12
y
=
−
7
4
Step 4: Multiply both sides by 12/7.
(
12
7
)
*
(
7
12
y
)
=
(
12
7
)
*
(
−
7
4
)
y
=
−
3
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