Solve : 7y = -3y2 - 4
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7y = -3y2 - 4
3y2 + 7y + 4 = 0
3y2 + 3y + 4y + 4 = 0
3y ( y + 1 ) 4 ( y + 1 )
( y + 1 ) ( 3y + 4 )
y + 1 = 0 , and 3y + 4 = 0
y = -1 and. 3y = - 4
y = -1 and. y = -4/3
here is your answer
3y2 + 7y + 4 = 0
3y2 + 3y + 4y + 4 = 0
3y ( y + 1 ) 4 ( y + 1 )
( y + 1 ) ( 3y + 4 )
y + 1 = 0 , and 3y + 4 = 0
y = -1 and. 3y = - 4
y = -1 and. y = -4/3
here is your answer
Answered by
1
7y= -3y 2-4. 12 factors= 3 &4
3y2+7y+4=0
3y2+3y+4y+4=0
3y (y+1) +4 (y+1)=0
(y+1) (3y+4)=0
y+1=0 or 3y+4=0
y=-1. 3y=-4
y= -4/3.
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