solve a^2x+b^2y-c^2=0 and b^2x+a^2y-d^2=0
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Answer:x+y= (c^2+d^2)/(a^2+b^2)
Step-by-step explanation:
Adding both equations we get :
a^2x+b^2x+a^2y+b^2y-c^2-d^2=0
x(a^2+b^2)+y(a^2+b^2)=c^2+d^2
(x+y)(a^2+b^2)=c^2+d^2
x+y=(c^2+d^2)/(a^2+b^2)
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