Question

solve a^2x+b^2y-c^2=0 and b^2x+a^2y-d^2=0

Answer 1

Answer:x+y= (c^2+d^2)/(a^2+b^2)

Step-by-step explanation:

Adding both equations we get :

a^2x+b^2x+a^2y+b^2y-c^2-d^2=0

x(a^2+b^2)+y(a^2+b^2)=c^2+d^2

(x+y)(a^2+b^2)=c^2+d^2

x+y=(c^2+d^2)/(a^2+b^2)