Question

Solve- (a)4x+4/6x+7 - x+1/2x+3 = 0

Answer 1

Answer :

• $\sf \frac{4x + 4}{6x + 7} - \frac{x - 1}{2x + 3} = 0$

$\longrightarrow$ Here,

First of all we need same denominator for solve the problem

• $\sf \frac{(2x + 3)(4x + 4) - (6x + 7)(x + 1)}{(6x + 7)(2x + 3)} = 0$

• (2x + 3) (4x + 4) - (6x + 7) (x + 1) = [(6x + 7)(2x + 3)] (0)

• 2x (4x + 4) + 3(4x + 4) - 6x (x + 1) + 7(x + 1) = 0

• 8x² + 8x + 12x + 12 - 6x² - 6x + 7x + 7 = 0

• 2x² + 21x + 19 = 0

$\longrightarrow$ Now, we have quartic equation

$\longrightarrow$ So, we need to factories it.

• 2x² + 21x + 19 = 0

2× 19 = 48

Hence,

• 2x² + 2x + 19x + 19 = 0

• 2x ( x + 1 ) + 19 ( x + 1 ) = 0

• (2x + 19) + (x + 1) = 0

First we have to solve (2x + 19) = 0

• 2x + 19 = 0

• 2x = -19

• $\sf \red{\underline{\underline{x = \frac{-19}{2}}}}$

Now we have to solve (x + 1 ) = 0

• x + 1 = 0

• $\sf \red{\underline{\underline{x = - 1 }}}$

I hope it helps you ❤️✔️