Solve : a man drop a 10 kg stone from the height of 5 m.
1) calculate speed just before it hits the ground
2) what is the kinetic energy when it just strikes the ground?? ( g=10m/s^2)
PLEASE MENTION METHOD TOO.... THANK YOU!!
Answers
Answered by
0
v^2=u^2+2aS
v^2=0+2*10*5
v=10m/s
K=1/2*m*v^2
K=1/2*10*100
K=500J
v^2=0+2*10*5
v=10m/s
K=1/2*m*v^2
K=1/2*10*100
K=500J
Similar questions