Question

solve:
a³+b³+c³+3abc
if a =3 b= -3 c = 2

please help with the question
question for class6 ​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer

-46

Step-by-step explanation:

Given Expression is

$a^3+b^3+c^3+3abc$

Putting a= 3 b=-3 and c=2

$(3)^3+(-3)^3+(2)^3+3(3)(-3)(2)\\= 27+(-27)+8+(-54)\\=27-27+8-54\\=8-54\\=-46$

Note- The cube of any negative integer is negative