solve above example with Arithmetic Progression 5th example
Plz tomorrow will be board exam 10 th std
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According to given condition,
(a – 2d) + (a + 3d) = 5 + (a – d) + (a + 3d)
(a – 2d) = 5 + (a – d)
a – 2d – a + d = 5
∴ -d = 5
∴ d = –5
∴ Also Temperature on Wednesday = –30º
∴ a = –30ºC
∴ Temperatures on remaining five days is
Monday = a – 2d = –30 – 2 × (–5) = –20ºC
Tuesday = a – d = –30 –(–5) = –25ºC
Thursday = a + d = –30 + (–5) = –35º
Friday = a + 2d = –30 + 2 × (–5) = –40ºC
Saturday = a + 3d = –30 + 3 × (–5) = –45ºC
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