Question

solve above example with Arithmetic Progression 5th example
Plz tomorrow will be board exam 10 th std​

Answer 1

According to given condition,

(a – 2d) + (a + 3d) = 5 + (a – d) + (a + 3d)

(a – 2d) = 5 + (a – d)

a – 2d – a + d = 5

∴ -d = 5

∴ d = –5

∴ Also Temperature on Wednesday = –30º

∴ a = –30ºC

∴ Temperatures on remaining five days is

Monday = a – 2d = –30 – 2 × (–5) = –20ºC

Tuesday = a – d = –30 –(–5) = –25ºC

Thursday = a + d = –30 + (–5) = –35º

Friday = a + 2d = –30 + 2 × (–5) = –40ºC

Saturday = a + 3d = –30 + 3 × (–5) = –45ºC