Math, asked by ItZTanisha, 3 months ago

Solve above question​

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Answered by guardianangelx
3

Let Present Age Of Jacob = x years

& present age of Jacob's son = y years

Five years hence (later)

Jacob's age = X+5

Jacob's son age = y+5

Age of Jacob will be three times of his son

x+5= 3 ( y + 5 )

x+5= 3y + 15

x-3y = 15-5

x-3y = 10 ...(1)

Also ,

Five Years Ago,

Jacob's Age = x-5

Jacob's Son Age = y-5

Age of Jacob was seven time of his son

x-5=7 ( y - 5 )

x-5=7y - 7(5)

( 3y + 10 )- 7y = - 30

3y + 10 - 7y = -30

-4y = -30-10

-4y = -40

y = -40/-4

y = 10

Putting y = 10 in (1)

x-3y = 10

x-3(10) = 10

x-30 = 10

x=10+30

X=40

So, x=40 , y=10

Thus Present Age of Jacob = x = 40 years

Present Age of Jacob Son = y = 10 years

Answered by Thatsomeone
3

arey thanks for so many thanks

btw tu marathi aahes na

kuthli city ?

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