Question

solve the quadratic equation: √3x²+√2x-2√3=0​

Answer 1

$\sqrt{3} {x}^{2} + 2\sqrt{2} x - 2 \sqrt{3} = 0 \\ \\ = > \sqrt{3} {x}^{2} + 3 \sqrt{2} x - \sqrt{2} x - 2 \sqrt{3} = 0 \\ \\ = > \sqrt{3} x(x + \sqrt{6} ) - \sqrt{2} (x + \sqrt{6} ) = 0 \\ \\ = > (x + \sqrt{6} )( \sqrt{3} x - \sqrt{2} ) = 0$