Question

Solve all the four problems given.Show the necessary calculations how you arrive at the answer.

Answer 1

1ans)
The series we have,
2 , 5 , 10 , 17 , ? , 37 , 50 , 65 , 82

2,(2+3),(5+5),(10+7),(17+9),(26+11),(37+13),
(50+15),(65+17)

Therefore the answer is 17+9=26


2ans)
The series we have,
2 , 2 , 256
3 , 2 , ?
4 , 2 , 46656

The pattern for last number is
(1st number + second number)^(1st +2nd number).
Now we have,
(2+2)^(2+2)=4^4=256

(3+2)^(3+2)=5^5=3125

(4+2)^(4+2)=6^6=46656

Hence the answer is 3125


3ans)
The series we have ,
1 , 3 , 7
5 , 12 , 14
25 , ? , 28
125 , 192 , 56
The pattern we have,
1=1×5^0=1
5=1×5^1=5
25=1×5^2=25
125=1×5^3=125

3=3×4^0=3
12=3×4^1=12
?=3×4^2=48
125=3×4^3=192

7=7×2^0=7
14=7×2^1=14
28=7×2^2=28
56=7×2^3=56

Hence the answer is 48


4ans)
The series we have,
16 , 210 , 14
14 , 156 , 12
12 , ? , 10
The pattern is for middle term , we have
16×14-14=224-14=210
14×12-12=168-12=156
12×10-10=120-10=110

Hence the answer 110

Answer 2

5.
add 2+2=4
and multiple 4*4*4*4=256
add 4+2=6
and multiple 6*6*6*6*6*6=46656
3+2=5
and multiple 5*5*5*5*5=3125
6.
5/1=5
12/3=4
14/7=2
column 1 multiples of 5 so,1,5,25,125
column 3 multiples of 2 so 7,14,28,56
column 2 multiples of 4
ans is 12*4=48
7.
(16+14)*(14/2)=30*7=210
(14+12)*(12/2)=26*6=156
(10+12)*(10/2)=22*5=110