Question

solve and don't spam or else I will report​

Answer 1

see the attachment...

I think it is correct...

Answer 2

$\huge \sf \color{lime}{Solution:- ~1}$

Here given: PQ = 11

distance between

Line PQ and line MN is 6

If distance between PQ and MN is 6

According to this theorem

Perpendicular drawn to chord from centre of its circle bisects the chord

$\huge \sf \color{lime}{Solution:-~2}$

So, if AOB = 6cm

then AO = 1/2 × AOB

AO = 1/2 × 6

= 3cm

According to this theorem perpendicular drawn from centre of circle.

Circle to its chord bisects the chord.

PA= 1/2×PQ

PA= 1/2×115.5

= 5:5

$\huge \sf \color{lime}{Solution:-~3}$

Applying phythagoran theoram

= Base×Height

=(5.5)^2 + (3)^2

=30.25+9

=(39.25)^2

=6.25cm