solve and find real roots p^2+4>0
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Answered by
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P^2 + 4 > 0
P^2 > -4
P^2 > (-2)^2
P > 2
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Answer:
p^2+4 > 0
p^2 > -4
p^2 > (-2)^2
p > ± 2
.: we get real roots as -2 and 2 .
Hope it helps you :-)
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