Math, asked by kprashantrajput001, 8 months ago

solve and find real roots p^2+4>0​

Answers

Answered by smilinggirl789
0

P^2 + 4 > 0

P^2 > -4

P^2 > (-2)^2

P > 2

Hope this answer will be helpful to you

plz mark as the brainlliest answer

Answered by 2003Sakshi
11

Answer:

p^2+4 > 0

p^2 > -4

p^2 > (-2)^2

p > ± 2

.: we get real roots as -2 and 2 .

Hope it helps you :-)

Similar questions