Question

Solve and Find the number of diagonalsin the

following polygons:

Triangle, Quadrilateral, Octagon, Decagon​

Answer 1

Step-by-step explanation:

Formula for finding the number of diagonals in any polygon= n(n-3)/2

n= number of sides in a polygon.

For triangle= n(n-3)/2

= 3(3-3)/2

=3(0)/2

= 0/2

=0

There are no diagonals in a triangle.

Quadrilateral= n(n-3)/2

= 4(4-3)/2

=4(1)/2

=4/2

=2

There are 2 diagonals in a quadrilateral.

Octagon= n(n-3)/2

=8(8-3)/2

=8(5)/2

=40/2

=20

There are 20 diagonals in a octagon.

Decagon = n(n-3)/2

=10(10-3)/2

=10(7)/2

=70/2

=35

There are 35 diagonals in a decagon.

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