Math, asked by jhasheaker, 1 day ago

solve and find the value of p(p-3)=6​

Answers

Answered by TarangGeetaAnil
0

Answer:

Solution:-

p(p-3)=6

p×(p-3)=6

p×p=p2(square)

p×-3=-3p

so the required quadratic equation will be

p2(square)-3p=6

to find the values of a,b,c

Solution:-

comparing p2-3p-6=0(standard form) with ax2-bx+c=0

we get a=1,b=-3,c=-6

Step-by-step explanation:

first thing is given

solve p(p-3)

this means multiplying (p-3) with p

then the eqn is clear.

then write it in standard form

and then compare it with ax2-bx+c=0

then we get the value of a,b,c

then solve the above

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