solve and find the value of p(p-3)=6
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Answer:
Solution:-
p(p-3)=6
p×(p-3)=6
p×p=p2(square)
p×-3=-3p
so the required quadratic equation will be
p2(square)-3p=6
to find the values of a,b,c
Solution:-
comparing p2-3p-6=0(standard form) with ax2-bx+c=0
we get a=1,b=-3,c=-6
Step-by-step explanation:
first thing is given
solve p(p-3)
this means multiplying (p-3) with p
then the eqn is clear.
then write it in standard form
and then compare it with ax2-bx+c=0
then we get the value of a,b,c
then solve the above
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