Question

solve and find the value of x​

Answer 1

$heya \\ \\ \\ \\ 2 {}^{x} \times 4 + 2 {}^{x} \div 2 = 9 \\ \\ \\ \\ = > \\ \\ \\ 2 {}^{x} (4 \div 1 \div 2) = 9 \\ \\ \\ 2 {}^{x} ( 9 \div 2 )= 9 \\ \\ \\ \\ 2 {}^{x} = 2 {}^{1} \\ \\ \\ x = 1$

Answer 2

${2}^{x + 2} + {2}^{x - 1} = 9 \\ {2}^{x} . {2}^{2} + {2}^{x} . {2}^{ - 1} = 9 \\ {2}^{x} ( {2}^{2} + {2}^{ - 1} ) = 9 \\ {2}^{x} (4 + \frac{1}{2} ) = 9 \\ {2}^{x} ( \frac{9}{2} ) = 9 \\ {2}^{x} = 9 \times \frac{2}{9} \\ {2}^{x} = 2 \\ x = 1$