Math, asked by Anonymous, 5 months ago

solve and simplify
2 {x}^{2}  - x + 1 = 0

Answers

Answered by Anonymous
16

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Q:-solve and simplify

2 {x }^{2} - x + 1 = 0

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➾</p><p>2 {x}^{2}  - x + 1 = 0

➾</p><p>2 {x}^{2}  - 2x + x + 1 = 0

➾</p><p>2x(x - 1) - 1(x - 1) = 0

➾</p><p>(2x - 1)(x - 1) = 0

➾</p><p>2x - 1 = 0

➾</p><p>x =  \frac{1}{2}

➾</p><p>x - 1 = 0

➾</p><p>x = 1

HOPE IT HELPS YOU..

_____________________

Thankyou:)

Answered by Anonymous
190

Answer:

➾2x

2

−x+1=0

➾ 2 {x}^{2} - 2x + x + 1 = 0➾2x

2

−2x+x+1=0

➾ 2x(x - 1) - 1(x - 1) = 0➾2x(x−1)−1(x−1)=0

➾ (2x - 1)(x - 1) = 0➾(2x−1)(x−1)=0

➾ 2x - 1 = 0➾2x−1=0

➾ x = \frac{1}{2}➾x=

➾ x - 1 = 0➾x−1=0

➾ x = 1➾x=1 ✓

HOPE IT HELPS YOU

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