solve and verify 3(t-3)=5 (2t-2)
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3(t-3)=5(2t-2)
= 3t-9=10t-10
= 10-9=10t-3t
= 1=7t
=1/7=t
Therefore the value of t is 1/7
Verification:
3(t-3)=5(2t-2)
If t=1/7
3(1/7-3)=5(2/7-2)
= 3(1-(3*7)/7)=5(2-(2*7)/7)
= 3(1-21/7)=5(2-14/7)
= 3(20/7)=5(12/7)
= 60/7=60/7
Hence,verified
= 3t-9=10t-10
= 10-9=10t-3t
= 1=7t
=1/7=t
Therefore the value of t is 1/7
Verification:
3(t-3)=5(2t-2)
If t=1/7
3(1/7-3)=5(2/7-2)
= 3(1-(3*7)/7)=5(2-(2*7)/7)
= 3(1-21/7)=5(2-14/7)
= 3(20/7)=5(12/7)
= 60/7=60/7
Hence,verified
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