solve any 2 question for brainlist
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♣(17) The angles of a triangle are x, y and 40° . The difference between the two angles x and y is 30° . Find x and y.
SOLUTION :-
Given angles of a triangle are x, y and 40° .
So, x + y + 40° = 180°
=> x + y = 180° – 40°
=> x + y = 140° ...{1}
And also given that, the difference between the two angles x and y is 30° .
So, x – y = 30° ...{2}
Subtracting {1} and {2} ,
x + y = 140°
x – y = 30°
_________
2y = 110°
y = 55°
Substituting the value of y in {2} ,
x – 55° = 30°
x = 30° + 55°
x = 85°
Hence, the values of angle x and y are 85° and 55° respectively.
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♣(11) Solve for x and y :
217x + 131y = 913 , 131x + 217y = 827
SOLUTION :-
Given equations :
217x + 131y = 913 ...{1}
131x + 217y = 827 ...{2}
Multiplying {1} by 131 and {2} by 217 ,
28427x + 17161y = 119603 ...(a)
28427x + 47089y = 179459 ...(b)
Subtracting (a) from (b) ,
28427x + 47089y = 179459
28427x + 17161y = 119603
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29928y = 59856
y = 2
Substituting the value of y in {2} ,
131x + 217(2) = 827
131x + 434 = 827
131x = 827 – 434
131x = 393
x = 3
Hence, the values of x and y are 3 and 2 respectively.
______________________________
______________________________
♣(17) The angles of a triangle are x, y and 40° . The difference between the two angles x and y is 30° . Find x and y.
SOLUTION :-
Given angles of a triangle are x, y and 40° .
So, x + y + 40° = 180°
=> x + y = 180° – 40°
=> x + y = 140° ...{1}
And also given that, the difference between the two angles x and y is 30° .
So, x – y = 30° ...{2}
Subtracting {1} and {2} ,
x + y = 140°
x – y = 30°
_________
2y = 110°
y = 55°
Substituting the value of y in {2} ,
x – 55° = 30°
x = 30° + 55°
x = 85°
Hence, the values of angle x and y are 85° and 55° respectively.
______________________________
♣(11) Solve for x and y :
217x + 131y = 913 , 131x + 217y = 827
SOLUTION :-
Given equations :
217x + 131y = 913 ...{1}
131x + 217y = 827 ...{2}
Multiplying {1} by 131 and {2} by 217 ,
28427x + 17161y = 119603 ...(a)
28427x + 47089y = 179459 ...(b)
Subtracting (a) from (b) ,
28427x + 47089y = 179459
28427x + 17161y = 119603
______________________
29928y = 59856
y = 2
Substituting the value of y in {2} ,
131x + 217(2) = 827
131x + 434 = 827
131x = 827 – 434
131x = 393
x = 3
Hence, the values of x and y are 3 and 2 respectively.
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