solve any of the following
Attachments:
mdanas71:
hii koi faceboob chalta hai
Answers
Answered by
0
Coaching kiya kro dost...
Answered by
2
heya....
i m doing que. no 21 (bcause it is easiest :D)
pH of water = 7
now .01 mole of NaOH is added in 10 lit . so Molality (conc.) of NaOH is .01/10 =10^-3 .
now by inverse log. the pH comes out to be = 11
So change in pH is 11-7 =4.
Here is your Ans.
(p.s. I am also THALA DHONI Fan...... MSD CSK LOVE❤❤)
i m doing que. no 21 (bcause it is easiest :D)
pH of water = 7
now .01 mole of NaOH is added in 10 lit . so Molality (conc.) of NaOH is .01/10 =10^-3 .
now by inverse log. the pH comes out to be = 11
So change in pH is 11-7 =4.
Here is your Ans.
(p.s. I am also THALA DHONI Fan...... MSD CSK LOVE❤❤)
how that inverse log becomes 11
hi manisha
Its 14 - inverse log.
please can you say clearly
bcausee when we Want to calculate basic pH we have to Substract it by 14
NaOH added is a base
When we take inverse log of its concentration we will get pOH now to convert pOH into pH we have to substract it by 14
okk tq
i hope u understand
ok welcome #dhonifan...
Similar questions