Question

Solve anyone , I need process { not all , only one but with process }

Answer 1

Answer :

(1)

Now, sinA = 1/√2

⇒ sinA = sin45°, when 0° < A < 90°

⇒ A = 45°

Also, sinA = 1/√2

⇒ sinA = sin135°

⇒ A = 135°

In 1st and 2nd quadrant, sine is always positive.

Hence, we have two values of A,

A = 45°, 135°

These values are the simple values of A.

Now, we proceed to find a general solution for A.

Here, sinA = 1/√2

⇒ sinA = sin45°

Hence, A = nπ + (- 1)ⁿα, where α = 45° and n be Natural number.

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Answer 2

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