Math, asked by T0PPER, 11 months ago

Solve ax^3+2x^2-3 if x=2 hence find the remainder

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Answered by arshbbcommander

1

Answer:

$\huge\bold\red{SOLUTION}$ $\bold\purple{♡FollowMe♡}$

if x =2

a(2)³ + 2(2)²-3 =0

8a + 8 -3 =0

8a +5 =0

8a = -5

a = -5/8

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