solve √ax+b +√ax-b /√ax-b -√ax-b=2
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Your question needs a correction.
= > √( ax + b ) + √( ax - b ) = 2√( ax + b ) - 2√( ax - b )
= > 2√( ax - b ) + √( ax - b ) = 2√( ax + b ) - √( ax + b )
= > 3√( ax - b ) = √( ax + b )
Square on both sides,
= > 9( ax - b ) = ax + b
= > 9ax - 9b = ax + b
= > 9ax - ax = b + 9b
= > 8ax = 10b
= > x = 5b / 4a
Second method is given in the attached file.
= > √( ax + b ) + √( ax - b ) = 2√( ax + b ) - 2√( ax - b )
= > 2√( ax - b ) + √( ax - b ) = 2√( ax + b ) - √( ax + b )
= > 3√( ax - b ) = √( ax + b )
Square on both sides,
= > 9( ax - b ) = ax + b
= > 9ax - 9b = ax + b
= > 9ax - ax = b + 9b
= > 8ax = 10b
= > x = 5b / 4a
Second method is given in the attached file.
Attachments:
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