solve:- ax+by=5;bx+ay=3,where a & b are constant term.
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Therefore ,
and
Step-by-step explanation:
Given,
ax+by = 5..........(1)
bx+ay=3...........(2)
Equation (1)×b -equation(2)×a we get
abx +b²y-abx-a²y=5b -3a
⇔(b²-a²)y=5b -3a
Putting the value of y in equation (1)
Therefore ,
and
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