Solve : ax+by = a-b bx-ay =a+b by elimination by SUBSTITUTION only.
Answers
Answered by
867
ax+by=a-b
ax=a-b-by
x=a-b-by/a←
bx-ay=a+b
substituting
b(a-b-by/a)-ay=a+b
ab-b²-b²y/a-ay=a+b
ab-b²-b²y-a²y/a=a+b
ab-b²-(b²+a²)y=a²+ab
-(b²+a²)y=a²+ab-ab+b²
(b²+a²)y=-(a²+b²)
y=-(a²+b²)/a²+b²
y=-1←
substituting value of y
x=a-b-b(-1)/a
x=a-b+b/a
x=a/a
x=1
ax=a-b-by
x=a-b-by/a←
bx-ay=a+b
substituting
b(a-b-by/a)-ay=a+b
ab-b²-b²y/a-ay=a+b
ab-b²-b²y-a²y/a=a+b
ab-b²-(b²+a²)y=a²+ab
-(b²+a²)y=a²+ab-ab+b²
(b²+a²)y=-(a²+b²)
y=-(a²+b²)/a²+b²
y=-1←
substituting value of y
x=a-b-b(-1)/a
x=a-b+b/a
x=a/a
x=1
Answered by
10
The value of x is 1 and y is -1.
Given,
Two equations ax+by = a-b and bx-ay =a+b
To Find,
The value of x and y using the substitution method.
Solution,
The given equation is
ax+by=a-b
ax=a-b-by
Using substitution method.
x=a-b-by/a
Substituing the value of x in other equation.
b(a-b-by/a)-ay=a+b
ab-b²-b²y/a-ay=a+b
ab-b²-b²y-a²y/a=a+b
ab-b²-(b²+a²)y=a²+ab
-(b²+a²)y=a²+ab-ab+b²
(b²+a²)y=-(a²+b²)
y=-(a²+b²)/a²+b²
y=-1
substituting the value of y
x=a-b-b(-1)/a
x=a-b+b/a
x=a/a
x=1
Hence, the value of x is 1 and y is -1.
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