Question

solve ax + by + c = 0 and bx + ay + b = 0​

Answer 1

Answer:

ax + by + c = 02 and bx + ay + b = 0

Answer 2

Answer:

x=(b^2-ac)/(a^2-b^2)     and               and y=(bc-ab)/(a^2-b^2)

Step-by-step explanation:

WE HAVE

ax+by+c=0

bx+ay+b=0

abx+b^2y+bc-abx-a^2y-ab=0

=>(a^2-b^2)y=bc-ab

=>y=(bc-ab)/(a^2-b^2)

similarlly

a^2x+aby+ac-b^2x-aby-b^2=0

=>x=(b^2-ac)/(a^2-b^2)