Solve ax+by-c, bx+ay=1+c by cross multiplication method.
Plz tell any one me
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Answer:
The given system of equations may be written as
ax+by−c=0
bx+ay−(1+c)=0
By cross-multiplication, we have
b×−(1+c)−a×−c
x
=
a×−(1+c)−b×−c
−y
=
a×a−b×b
1
⇒
−b(1+c)+ac
x
=
−a(1+c)+bc
−y
=
a
2
−b
2
1
Hope u r satisfied ❤✌
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