Chemistry, asked by bhumika0246, 7 months ago


The decrease in concentration of NO2 in the reaction, 2NO2 + 2NO+ O2, is 4 x 10-13 mol L-s-1
What is the increase in the rate of concentration of O2?​

Answers

Answered by Anonymous
2

Answer:

(a)

rate = k∙[O₂(g)]∙[NO₂(g)]²

(b)

rate = 7480M⁻²s⁻¹ ∙ (0.0191M) ∙(0.0302M)² = 0.1303M/s

(c)

since is first with respect to oxygen the rate doubles so

rate = 0.2606M/s

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