Question

solve: (b)9/11-4/15​

Answer 1

$\Large\bf{\underline{\underline{Question:-}}}$

Solve:

$\Large\sf\frac{9}{11} - \frac{4}{15}$

$\Large\bf{\underline{\underline{Solution:-}}}$

Here,

$\Large\sf\frac{9}{11} - \frac{4}{15}$

Taking LCM of 11 and 15, we have

= $\Large\sf\frac{135 - 44}{165}$

= $\Large\sf\frac{91}{165}$

Hence the required value is $\Large{\boxed{\frac{91}{165}}}$

$\pink{Hope \: it \: helps}$

Answer 2

$\tt \huge {\boxed {\mathbb {QUESTION}}}$

$\tt {solve:}$

$\tt \dfrac{9}{11}-\dfrac{4}{15}$

$\tt \huge {\boxed {\mathbb {ANSWER}}}$

$\tt \implies \dfrac{9}{11}-\dfrac{4}{15}$

$\tt {By\:Taking\:LCM}$

$\tt \implies \dfrac{135-44}{165}$

$\tt \implies \dfrac{91}{165}$

$\tt \huge {\boxed {\mathbb {HOPE \:IT \:HELPS \:YOU}}}$

_________________________________________

$\tt \huge {\boxed {\mathbb {EXTRA\:INFORMATION}}}$

$\tt {Identities}$

$\tt {(a+b)}^{2}={a}^{2}+2ab+{b}^{2}$

$\tt {(a-b)}^{2}={a}^{2}-2ab+{b}^{2}$

$\tt (a+b) (a-b) ={a}^{2}-{b}^{2}$

$\tt{\mathbb{\colorbox {orange} {\boxed{\boxed{\boxed{\boxed{\boxed{\colorbox {lime} {\boxed{\boxed{\boxed{\boxed{\boxed{\colorbox {aqua} {@suraj5070}}}}}}}}}}}}}}}$