Question

solve b+c/bc(b+c-a) + c+a/ca(c+a-b) + a+b/ab(a+b-c)​

Answer 1

Answer:

L.H.S = (a – b) (a + b) + (b – c) (b + c) + (c – a) (c + a)

Using identity:

(a – b) (a + b) = a2 – b2

We get,

= (a2 – b2) + (b2 – c2) + (c2 – a2)

= a2 – b2 + b2 – c2 + c2 – a2

= 0

= R.H.S

Hence, verified

Answer 2

Answer:

a+b= 1-c

b+c = 1-a

c+a = 1-b

(1/a)+(1/b)+(1/c) = 3

multiply both sides by (abc) ,

we get

bc+ac+ab = 3abc

ab+bc+ac-3abc = 0

=> (1-c)ab + (1-a)bc + (1-b)ac

=> ab-abc+bc-abc+ac-abc

=> ab+bc+ac-3abc

=>0

Step-by-step explanation:

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