Question

solve both questions...

Answer 1

HELLO DEAR,


----------------------(1)----------------------------

$\frac{ {sin}^{ 3} \alpha - {cos}^{3} \alpha }{sin \alpha - cos \alpha } \\ \\ = \frac{(sin \alpha - cos \alpha )( {sin}^{2} \alpha + {cos}^{2} \alpha + sin \alpha cos \alpha) }{(sin \alpha - cos \alpha )} \\ \\ = 1 + sin \alpha cos \alpha$


--------------------------(2)---------------------------

(1+ tan² A) / (1+ cot² A)

=> (1+ tan² A) / (1+ 1 / tan² A)

=> (1+ tan² A) / [(tan² A+ 1)/tan² A)]

=> tan²A


I HOPE ITS HELP YOU DEAR,
THANKS

Answer 2

Hope it helps you!!
Mark it as brainliest plzz!!