Question

Solve both the questions plz:
19 and it's or.
It's urgent!!!!

Answer 1

(1) Question is incorrect.

(2) 

Given sectheta = x + 1/4x

On squaring both sides, we get

(sectheta)^2 = (x + 1/4x)^2

sec^2theta = x^2 + 1/16x^2 + 2 * x * 1/4x

sec^2theta = x^2 + 1/16x^2 + 1/2

We know that tan^2theta + 1 = sec^2 theta 

1 + tan^2 theta = x^2 + 1/16x^2 + 1/2

tan^2 theta = x^2 + 1/16x^2 + 1/2 - 1

tan^2 theta = x^2 + 1/16x^2 - 1/2

$tan theta = +(x - \frac{1}{4x}) and -(x - \frac{1}{4x})$


Now,

When tantheta = +(x - 1/4x) 

tan theta + sectheta = x + 1/4x + (x - 1/4x)

                                 = x + 1/4x + x - 1/4x

                                 = 2x.


When tantheta = -(x - 1/4x)

tan theta + sectheta = x + 1/4x - (x - 1/4x)

                                 = x + 1/4x - x + 1/4x

                                 = 2/4x

                                 = 1/2x.


Hope this helps!