Question

solve by calendering.
14 may 2000 -which day​

Answer 1

Answer:

sunday

28th May 2006 = (2005 years + period from 1-Jan-2006 to 28-May-2006)

We know that number of odd days in 400 years = 0

Hence the number of odd days in 2000 years = 0 (Since 2000 is a perfect multiple of 400)

Number of odd days in the period 2001-2005

= 4 normal years + 1 leap year

= 4 x 1 + 1 x 2 = 6

Days from 1-Jan-2006 to 28-May-2006 = 31 (Jan) + 28 (Feb) + 31 (Mar) + 30 (Apr) + 28(may)

= 148

148 days = 21 weeks + 1 day = 1 odd day

Total number of odd days = (0 + 6 + 1) = 7 odd days = 0 odd day

0 odd day = Sunday

Hence May 28 2006 is Sunday.

Answer 2

Answer:

14 may 2000 was Sunday....