Question

solve by comparison method :
x-y = 2
2x-3y= 1​

Answer 1

in this question,,A1=1,B1=-1,C1=2 and,,A2=2,B2=-3,C2=1

Hence,,X=(B1C2-C1B2)/(A1B2-B1A2)

=(-1)(1)-2×(-3)/(1)(-3)-(-1)(2)

=-1+6/-3+2

=5/-1

=-5

Since,Y=(C1A2-A1C2)/(A1B2-B1A2)

You can solve after this..

Answer 2

Answer:

value of x is $\frac{7}{5}$ and y is $\frac{-3}{5}$

Step-by-step explanation:

given, x - y = 2  ___eq(1)

          2x - 3y = 1 ___eq(2)

multiply eq(1) by 2

2(​x - y) = 2(2)

2x - 2y = 4 ___eq(3)

subtract eq(3) from eq(2)

2x - 2y = 4

2x - 3y = 1

0 - 5y  = 3

$y = \frac{-3}{5}$

substitute the value of 'y' in eq (1)

$x - \frac{(-3)}{5} =2\\ x+\frac{3}{5}=2\\ x = 2-\frac{3}{5}$

$x = \frac{10-3}{5}= \frac{7}{5}$

therefore, value of x is $\frac{7}{5}$ and y is $\frac{-3}{5}$