Question

Solve by 'completing of square' or 'quadratic equation'

$2. \: x {}^{2} + 2 \sqrt{2}x - 6 = 0$
Ans:
$\sqrt{2} \: \: , \: \: - 3 \sqrt{2}$


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Answer 1

Hey!!!!

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As promised I am here to help you

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We have,

=> x² + 2√2x - 6 = 0

=> x² + 2√2x = 6

See for using competing the square method, the leading co efficient of the equation must be 1.

Here it is already there so we will add the square of the half of the co efficient of x on both sides

=> x² + 2√2x + (√2)² = 6 + 2

=> (x + √2)² = 8

Now

=> (x + √2) = + - √8

=> x + √2 = + 2√2 or x + √2 = - 2√2

Thus

=> x = √2 or x = - 3√2 <<<<<< Answer

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Answer 2

The answer is attached below.



Hope it helps!