solve by completing square method
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QUESTION:-
5x²-4x-3=0
Solving it by method of completing the square:-
- make coefficient of x² independent
- so, multiply 1/5 from LHS and RHS
1/5(5x²-4x-3)=1/5(0)
=>x²-4/5x-3/5=0-----(1)
- Now, split the middle term ..just see how I split
-4/5x = -2ax { •°• a =? , b=x}
4/5=2a
4/10=a
or,
a= 2/5
so, we find a= 2/5 and b=x
Now,
putting the splited term in eq(1):-
=>(2/5)²-2(2/5)(x)+ x²=0
=>(x-2/5)²=0
=>(x-2/5)=0
=>x=2/5
HENCE, x=2/5
I hope you understand ! .. method of completing the square
☺️✌️✌️
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