Question

solve by Cramer's rule 8x+3y=2, y+3z=7, 2x+2z=8​

Answer 1

Given:

8x + 3y = 2, y + 3z = 7, 2x + 2z = 8​

To find:

Solve by Cramer's rule.

Solution:

From the given information, we have the data as follows.

8x + 3y = 2, y + 3z = 7, 2x + 2z = 8​

We are asked to solve these equations using Cramer's rule.

Write the given equations in terms of matrix.

8   3   0  

0   1   3    

2   0   2  

⇒ Δ = 34

Now compute Δ₁

2   3   0  

7   1   3    

8   0   2  

⇒ Δ₁ = 34

Now compute Δ₂

8   2   0  

0   7   3    

2   8   2  

⇒ Δ₂ = -68

Now compute Δ₃

8   3   2  

0   1   7    

2   0   8  

⇒ Δ₃ = 102

Now, we will solve for the variables.

x = Δ₁/Δ

x = 34/34

x = 1

y = Δ₂/Δ

y = -68/34

y = -2

z = Δ₃/Δ

z = 102/34

z = 3

Therefore, the values are x = 1, y = -2 and z = 3

Answer 2

Answer:

Exercise

1) Solve by Cramer's rule

8x+3y=2 , y+3z=7 , 2x+2z=8