solve by Cramer's rule 8x+3y=2, y+3z=7, 2x+2z=8
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Answered by
8
Given:
8x + 3y = 2, y + 3z = 7, 2x + 2z = 8
To find:
Solve by Cramer's rule.
Solution:
From the given information, we have the data as follows.
8x + 3y = 2, y + 3z = 7, 2x + 2z = 8
We are asked to solve these equations using Cramer's rule.
Write the given equations in terms of matrix.
8 3 0
0 1 3
2 0 2
⇒ Δ = 34
Now compute Δ₁
2 3 0
7 1 3
8 0 2
⇒ Δ₁ = 34
Now compute Δ₂
8 2 0
0 7 3
2 8 2
⇒ Δ₂ = -68
Now compute Δ₃
8 3 2
0 1 7
2 0 8
⇒ Δ₃ = 102
Now, we will solve for the variables.
x = Δ₁/Δ
x = 34/34
x = 1
y = Δ₂/Δ
y = -68/34
y = -2
z = Δ₃/Δ
z = 102/34
z = 3
Therefore, the values are x = 1, y = -2 and z = 3
Answered by
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Answer:
Exercise
1) Solve by Cramer's rule
8x+3y=2 , y+3z=7 , 2x+2z=8
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