Solve by cross multiplication method .
2u-7v equals -1
4u +3v equals 15
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2u - 7v = -1
2u = 7v - 1
u = (7v - 1)/2 ............(1)
4u + 3v = 15
Apply (1)
4[ (7v - 1)/2 ] + 3v = 15
2(7v - 1) + 3v = 15
14v + 3v = 15 + 2
17v = 17
v = 1
Apply (1)
u = (7-1)/2 = 6/2 = 3
So
u = 3; v = 1
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